Definition: Algebraic long division is very similar to traditional long division (which you may have come across earlier in your education). The easiest way to explain it is to work through an example.
Example of Algebraic Long Division
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhHIS6RAvQq6TKD0Z3mrfSUT-kpvwuNvnmpz2IeHWY3VAbz8g2_jv4Y7GXvnIbNwKPpXKhCsIBYpR08WR1o8782NdnjfbzpzIZ7f3-GiMo3D-N2WNAgcM-AaCWT1FnMZ8q9DNMpdCMDxWk/s320/untitled.bmp)
If the polynomial/ expression that you are dividing has a term in x missing, add such a term by placing a zero in front of it. For example, if you are dividing x³ + x - 4 by something, rewrite it as x³ + 0x² + x - 4 .
With algebraic long division, practice makes perfect- the best way to learn how to do them properly is to do loads of examples until you get them right every time.
The Factor Theorem
This states:
In the above worked example, f(2) = 0. This means that (x - 2) is a factor of the equation.
The factor theorem is important because it can be an easy way of finding factors that would otherwise be difficult to find.
Example
Factories x³- 7x - 6.
--> -->Example of Algebraic Long Division
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhHIS6RAvQq6TKD0Z3mrfSUT-kpvwuNvnmpz2IeHWY3VAbz8g2_jv4Y7GXvnIbNwKPpXKhCsIBYpR08WR1o8782NdnjfbzpzIZ7f3-GiMo3D-N2WNAgcM-AaCWT1FnMZ8q9DNMpdCMDxWk/s320/untitled.bmp)
If the polynomial/ expression that you are dividing has a term in x missing, add such a term by placing a zero in front of it. For example, if you are dividing x³ + x - 4 by something, rewrite it as x³ + 0x² + x - 4 .
With algebraic long division, practice makes perfect- the best way to learn how to do them properly is to do loads of examples until you get them right every time.
The Factor Theorem
This states:
- If (x – a) is a factor of the polynomial f(x), then f(a) = 0
In the above worked example, f(2) = 0. This means that (x - 2) is a factor of the equation.
The factor theorem is important because it can be an easy way of finding factors that would otherwise be difficult to find.
Example
Factories x³- 7x - 6.
Note that if we replace x by -1, then we get zero. If you notice or have been told this, then you know immediately, by the factor theorem, that one of the factors is (x + 1). Now we can divide
x³-7x - 6 by (x + 1) to find the other factors. If you carry out the division, you will get X²- x - 6.
This is easy to factories,the answer being (x - 3)(x + 2)
-->x³-7x - 6 = (x + 1)(x - 3)(x + 2)
When dividing one algebraic expression by another, more often than not there will be a remainder. It is often useful to know what this remainder is and it can often be calculated without going through the process of dividing. The rule is:
- If a polynomial f(x) is divided by ax - b, the remainder is f(b/a)
Let f(x) = 2x³ - 3x² - 3x + 2 . In this case, a = 1, b = 2. The remainder is therefore f(2) = 2×2³ - 3×2² - 3×2 + 2 = 0, as we saw when we divided the whole thing out.
Terminology
The quotient is what you are given after dividing. So, if p(x) is the original polynomial, then
p(x) = q(x)s(x) + r(x), where q(x) is the quotient, s(x) is what you are dividing by and r(x) is the remainder.